1.

Two equal charges q are kept fixed at a and +a along the x-axis. A particle of mass m and charge q/2 is brought to the origin and given a small displacement along the x-axis then

Answer»

the particle executes oscillartory motion
the particle remains stationary
the partiel executes, SHM along `x`-axis
the particle executes SHM along `y`-axis

Solution :(c) From coulomb's law,

`F=1/(4 epsilon_(0))(q_(1)q_(2))/(r^(2))`
`F=1/(4pi epsilon_(0))(qxxq/2)/((a+x)^(2))-1/(4piepsilon_(0)).(qxxq/2)/((a-x)^(2))`
`=1/(4piepsilon_(0))(q^(2))/2[1/((a+x)^(2))-1/((a-x)^(2))]`
`=1/(4piepsilon_(0).(q^(2))/2 [-(4AX)/((a^(2)-x^(2))^(2))]`
When `x lt lt a`, then
`F=-(2q^(2))/(4piepsilon_(0)a^(3))ximpliesF PROP -x`
Hence SHM isaklong `x`-axis.


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