Two equal resistances, 400 Omegaeach, are connected in series with a 8 V battery. If the resistance of first one increases by 0.5%, the change required in the resistance of the second one in order to keep the potential difference across it unaltered is to

Two equal resistances, 400 Omegaeach, are connected in series with a 8

1.	Two equal resistances, 400 Omegaeach, are connected in series with a 8 V battery. If the resistance of first one increases by 0.5%, the change required in the resistance of the second one in order to keep the potential difference across it unaltered is to
Answer» increase it by 1`OMEGA` increase it by 2`Omega` increase it by 4`Omega` decrease it by 4`Omega` SOLUTION :CaseI: VOLTAGEACROSS`R_1or R_2` `V_1=V_2=( 400 xx 8 )/( 800)= 4V ` Case II : ` R_1 . = R_1 + ( 0.5%)xx R_1 = 420Omega` ` V_(1) .=(8 )/( R_1 . +R_2.) xx R_2.` `implies4 = (8)/( 402+R_2.) xx R_2 .` `implies402+R_2 .= 2 R_2.implies R_2 . =402Omega ` ` DeltaR_2 =R_2. -R_2=402- 400= 2Omega `

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Two equal resistances, 400 Omegaeach, are connected in series with a 8 V battery. If the resistance of first one increases by 0.5%, the change required in the resistance of the second one in order to keep the potential difference across it unaltered is to

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