Two equal sides of a triangle are each 5 meters less than twice the th

1.	Two equal sides of a triangle are each 5 meters less than twice the third side. If the permeter of the triangle is 55 meters, find the length of its sides?
Answer» Given :- TWO equal sides of a triangle are each 5 meters less than twice the third SIDE. If the perimeter of the triangle is 55 meters, To Find :- Length of sides Solution :- Let the unequal side be x Then, equal side = 2x - 5 2x - 5 + 2x - 5 + x = 55 5x - 10 = 55 5x = 55 + 10 5x = 65 x = 65/5 x = 13 Sides of the triangle are x = 13 m x = 13 m 2x - 5 = 2(13) - 5 = 26 - 5 = 21 m

Two equal sides of a triangle are each 5 meters less than twice the third side. If the permeter of the triangle is 55 meters, find the length of its sides?

Answer»

TWO equal sides of a triangle are each 5 meters less than twice the third SIDE. If the perimeter of the triangle is 55 meters,

Length of sides

Let the unequal side be x

Then, equal side = 2x - 5

2x - 5 + 2x - 5 + x = 55

5x - 10 = 55

5x = 55 + 10

5x = 65

x = 65/5

x = 13

Sides of the triangle are

x = 13 m

2x - 5 = 2(13) - 5 = 26 - 5 = 21 m