two equal sides of a triangle are each 5 metres less than twice the th

1.	two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres find the length of its sides
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ Required answer: The lengths of the SIDES are 13 m, 21 m, 21 m. Given Information: Two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres. Need to FIND out: The lengths of the sides = ? $\underline{\underline{\underline{\underline{\mathfrak{\pink{ \:\:\: Explanation:-\:\:\:}}}}}} \\$ Let the third side of the triangle be y metres. Then, The two equal sides will be (2y - 5) m each. According to the problem, Perimeter of ΔABC = AB + BC + CA Perimeter of ΔABC = 55 m Therefore, => 2y - 5 + y + 2y - 5 = 55 =>⠀⠀⠀⠀⠀⠀⠀⠀5y - 10 = 55 => ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 5y = 65 => ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ y = 13 m So, Third side = 13 m => Other two sides = 2 × 13 - 5 => Other two sides = 26 - 5 => Other two sides = 21 m Therefore, The sides are 13 m, 21 m, 21 m $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$ => 13 + 21 + 21 => 13 + 42 => 55 m is the perimeter of ΔABC.

two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres find the length of its sides

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

Required answer:

The lengths of the SIDES are 13 m, 21 m, 21 m.

Given Information:

Two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres.

Need to FIND out:

The lengths of the sides = ?

$\underline{\underline{\underline{\underline{\mathfrak{\pink{ \:\:\: Explanation:-\:\:\:}}}}}} \\$

Let the third side of the triangle be y metres.

Then,

The two equal sides will be (2y - 5) m each.

According to the problem,

Perimeter of ΔABC = AB + BC + CA

Perimeter of ΔABC = 55 m

Therefore,

=> 2y - 5 + y + 2y - 5 = 55

=>⠀⠀⠀⠀⠀⠀⠀⠀5y - 10 = 55

=> ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 5y = 65

=> ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ y = 13 m

So,

Third side = 13 m

=> Other two sides = 2 × 13 - 5

=> Other two sides = 26 - 5

=> Other two sides = 21 m

Therefore,

The sides are 13 m, 21 m, 21 m

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$

=> 13 + 21 + 21

=> 13 + 42

=> 55 m is the perimeter of ΔABC.