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Two equal sides of a triangle are each 5 metres less than twice the third side. If theperimeter of the triangle is 55 metres, find the lengths of its sides.Tuo​

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ANSWER:

Let the third side be X m.

Let the third side be x m.Then the two EQUAL sides are of length (2x−5) m.

Let the third side be x m.Then the two equal sides are of length (2x−5) m.Perimeter of TRIANGLE = 55 m.

Let the third side be x m.Then the two equal sides are of length (2x−5) m.Perimeter of triangle = 55 m.⟹x+(2x−5)+(2x−5)=55

Let the third side be x m.Then the two equal sides are of length (2x−5) m.Perimeter of triangle = 55 m.⟹x+(2x−5)+(2x−5)=55⟹5x−10=55

Let the third side be x m.Then the two equal sides are of length (2x−5) m.Perimeter of triangle = 55 m.⟹x+(2x−5)+(2x−5)=55⟹5x−10=55⟹x=13

Let the third side be x m.Then the two equal sides are of length (2x−5) m.Perimeter of triangle = 55 m.⟹x+(2x−5)+(2x−5)=55⟹5x−10=55⟹x=13Hence, the length of the triangle's sides are 13m, 21m and 21m.


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