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Two events A and B will be independent, if (A) A and B are mutually exclusive (B) P (A’B’) = [1 – P(A)] [1 – P(B)] (C) P (A) = P (B) (D) P (A) + P (B) = 1 |
Answer» Answer is (B) P(A’B’) = P(A’∩B’) = PA ∪ B = 1 – P (A∪B) = 1 – P(A) – P(B) – P(A) – P(B) = 1 – P (A) – P (B) [1 – P (A)] = [1 – P (A)] [1 -P(B)] |
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