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Two events E and F are independent. If P(E )=0.3 and P(`EcupF`)=0.5 then `P(E//F)-P(F//E)` equals toA. `2/7`B. `3/35`C. `1/70`D. `1/7` |
Answer» Here, P(E )=0.3 and `P(EcupF)=0.5` Let P(F)=x ltbr gt`becauseP(EcupF)=P(E )+P(F)-P(EcapF)` `=P(E )+P(F)-P(E )cdotP(F)` `rArr0.5=0.3+x-0.3x` `rArrx=(0.5-0.3)/0.7=2/7=P(F)` `thereforeP(E//F)-P(F//E)=(P(EcapF))/(P(F))-(P(FcapE))/(P(E ))` `=(P(EcapF)cdotP(E)-P(FcapE)cdotP(F))/(P(E)cdotP(F))` `=(P(EcapF)[P(E)-P(F)])/(P(EcapF))=P(E)-P(F)` `=3/10-2/7=(21-20)/70=1/70` |
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