1.

Two faraday of electricity is passed through a solution of CuSO_(4). The mass of copper deposited at the cathode is (at. Ass of Cu=63.5 amu)

Answer»

0g
63.5g
2g
127g

Solution :`UNDERSET(2F)(Cu^(2+)+2e^(-))underset("1 MOLE")(TOCU)`
`=63.5g`


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