InterviewSolution
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InterviewSolution
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Two forces each equal to `F//2` act at right angle. Their effect may be neutralized by a third force acting along their bisector in the opposite direction. What is the magnitude of that third forces. |
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Answer» Rsultant of two forces:`sqrt((F//2^(2))+(F//2^(2)))=F//sqrt(2)` The third force, should be opposite to the resultant and of same magnitude. Hence, answer is `F//sqrt(2)`. |
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