1.

Two friends Rohan and Dayal want to invest their money in some kind of property.After a lot of research, they decide to buy a piece of land. Rohan comes across atriangular piece of land costing Rs. 1000 per sq meter with the land being uniform inlength all across. The land owner offers a total sale price of Rs. 25 lakhs. Dayal comes across a square piece of land at the rate of Rs. 6000 per sq. meter. He is expected to pay Rs. 54 lakhs for the land. Who do you think is getting a better offer? What will be the boundary length of each of the fields?

Answer»

Solution :-

Triangular piece of land :-

  • Total sale Price = Rs. 25 lakhs.
  • Rate = Rs. 1000 per sq meter .

So,

→ Area of Triangular piece of land = Total sale Price / Rate = (25,000,00/1000) = 2500 m² .

Now, SINCE ,the land being UNIFORM in length all across .

→ Area of Equaliteral ∆ = 2500 m² .

→ (√3/4) * (side)² = 2500

→ (side)² = 2500 * 4 / √3

→ (side)² = 10000/√3

→ (side)² = 5780.34

square root both sides ,

→ side = 76.02 m .

Similarly,

Square piece of land :-

  • Total sale Price = Rs. 54 lakhs.
  • Rate = Rs. 6000 per sq meter .

So,

→ Area of Square piece of land = Total sale Price / Rate = (54,000,00/6000) = 900 m² .

Now, since ,the land being uniform in length all across .

→ Area of Square = 900 m² .

→ (side)² = 900

square root both sides ,

→ side = 30 m .

Therefore, Rohan is getting a better Offer .

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