1.

Two full turns of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further it is found that the screw gauge has a zero error of -0.03 mm. While measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale division in line with the main scale as 35. The diameter of the wire is

Answer»

`3.32` MM
`3.73` mm
`3.67` mm
`3.38` mm

Solution :Least count of the screw gauge `=(0.5mm)/(50)=0.01mm,`
MAIN scale reading =`3mm`.
Vernier scale reading =`35`
`:.`Observed reading `=3+0.35=3.35`
zero ERROR`=-0.03`
`:.`ACTUAL diameter of the the wire `=3.35-(-0.03)`
`=3.38mm`
`(d)` is the correct CHOICE.


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