1.

Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49u. Molecular mass of B will be :

Answer»

50.00u
12.25u
6.50u
25.00u

Solution :`(r_(A))/( r_(B)) = sqrt(( M_(B))/( M_(A)))`
`( V//20)/( V//10) = sqrt((M_(B))/( 49))`
`(1)/(2) = sqrt((M_(B))/(49)) :. M_( B) = 49 xx (1)/( 4) = 12.25 `


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