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Two heater coils separately take 10 minutes and 5 minutes to boil a certain amount of water. Find the time taken by both the coils connected in series to boil the same amount of water . |
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Answer» Solution :`t_1 = 10` min `=t_1 = 5 ` min `implies 1/R=` constant `(t_1)/(t_2) =(R_1)/(R_2) implies(10)/5 =(R_1)/(R_2)` `therefore R_1 : R_2 = 2:1` Resultant resistance `R= R_1 + R_2 = 2R+R = 3R`. If 2R heater TAKES 10 minutes then 3R heater takes 15 minutes for heating purpose |
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