1.

Two hydrogen like atoms A and B having (N)/(Z) ratio equal to 1 have atomic number Z_(A) and Z_(B) A is moving, while B is stationary and both are in ground state. The minimum kinetic energy which A must have to have an inelastic collision with B such that both A and B getting excited is 221 e V. If situation is reversed and B is made to stike A which is stationary and both in ground state then minimum kinetic energy which B must have to make an inelastic coliision with both getting excited is331.5 e V. Assume mase of proton = mass of neutron. Inwhich of the following case energy of emitted photon will be same (Neglecting recoil of atom)

Answer»

A makes a TRANSITION from n=2 to 1 and B makes a transition from n = 4 to 2
A make a transition fromn = 4 to 2 and B makes a transition from n = 6 3.
A makes a transition from n = 2 to 1 and B makes a trasition from n = 6 to 3
A makes a transition from n = 6 to 3 and B makes a transition from n=8 to 4

Solution :`DELTAE = 13.6 ((1)/((n_(f)/(Z))^(2))-(1)/((n_(1)/(Z))^(2)))`


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