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Two ice skaters A and B approach each other at right angles. A has mass 30 kg and velocity 1 mis and B has a mass of 20 kg and velocity 2 m/s. They meet and stick together. The final velocity of couple is :

Answer»

Solution :Let v = COMPOSITE velocity after COLLISION, Q = ANGLE with the direction of 30 kg mass Then from momentum conservation,

`5vcos theta = 30 xx 1`
`50V sin theta =20 xx 2`
From equations (1) and (2)
`sqrt(50^(2).v^(2)) = sqrt(900 + 1600)`
50v= 50, v= 1m/s


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