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Two ice skaters A and B approach each other at right angles. A has mass 30 kg and velocity 1 m/s and B has a mass of 20 kg and velocity 2 m//s. They meet and stick together. The final velocity of couple is :

Answer»

Solution :Let v = COMPOSITE velocity after collision, `theta` = angle with the direction of 30 KG mass Thenfrom momentum conservation,
`50V cos theta=30xx1`
`50v sin theta =20xx2`
From EQUATIONS (1) and (2),
`sqrt((50)^(2)+v^(2))=sqrt(900+1600)`
`50v=50`
`v=1m//s`


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