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Two identical blocks A and B each of mass M are connected to each other through a light string. The system is placed on a smooth hori-zontal floor. When a constant force F is applied hori zontally on the block A, find the tension in the string. |
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Answer» Solution :The acceleration of the system of TWO blocks A and `B=("FORCE")/("Total MASS")` `THEREFORE a=(F)/(M+M)=(F)/(2M)`. If we consider the free body diagram of A, the forces acting on it are (i) the applied force F and (ii) the tension T on the string as SHOWN in the following fig.  The resultant force `= F-T , Ma = F-T` `M((F)/(2M))=F-T "" (therefore a=(F)/(2M))` `(F)/(2)=F-T`  `T=(F)/(2)` (or) From FBD for B `T=Ma=M(F)/(2M)=(F)/(2)` `T=(F)/(2)` 
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