InterviewSolution
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InterviewSolution
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Two identical capacitors are connected in the circuit shown. C_(2) is charged to 100 V and switch S is shifted from position 1 to position 2. The negative terminal of C_(2) is connected with the positive terminal of C_(1). Find the work done by the battery. If the polarity of C_(2) were reversed, what work would have been done by the battery ? |
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Answer» Solution :Case I :- `KVLrArr100-(2(1000+q))/(C )=0` `Q=500muC` WORK done by the BATTERY, `W=0.5xx10^(-3)xx100=0.05J` Case II :- `KVL` `rArr 100-(((q-1000))/(10))-(((q+1000))/(10))=0` `Q=500muC` `:. ` Work done by the battery, `W=DeltaqE=0.05J` 
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