Two identical capacitors are placed side by side with a small gap between them as shown in fig. V_(1) and V_2are potential difference across the two capacitors respectively. An electron is projected from the end of upper plate of the left capacitor with velocity v_0=sqrt((3V_(1)1^2e)/(4md^2))towards right as shown. Charge and mass of electron are .e. and .m. respectively. V_2is applied such that the electron just grazes the lower plate of right capacitor horizontally while coming out of it. Assume that there is no gravity and no collision of electron with any plate. What is the ratio V_2/V_1 ?

Two identical capacitors are placed side by side with a small gap betw

1.	Two identical capacitors are placed side by side with a small gap between them as shown in fig. V_(1) and V_2are potential difference across the two capacitors respectively. An electron is projected from the end of upper plate of the left capacitor with velocity v_0=sqrt((3V_(1)1^2e)/(4md^2))towards right as shown. Charge and mass of electron are .e. and .m. respectively. V_2is applied such that the electron just grazes the lower plate of right capacitor horizontally while coming out of it. Assume that there is no gravity and no collision of electron with any plate. What is the ratio V_2/V_1 ?
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