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Two identical circular coils are separated by a distance twice the radius of either of the coil. If n = 2, r = 0.08 m, i = 3A, then calculate the resultant magnetic field at the mid point of the line joining their centres, for currents in the same sense and opposite sense in the two circular coils. |
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Answer» Solution :Give : n =2, r = -0.08 m, i = 3A Magnetic field at a point on the axis, `""=(mu_(0)/(4PI))((2pinir^(2))/((r^(2)+x^(2))^(3//2)))` At P, `""B=(10^(-7) times 2 times 3.142 times 2 times 3 times r^(2))/(r^(2)+r^(2))^(3//2)` `""=(37.7 times 10^(-7) times r^(2))/(2.828 times r^(3))` `""=(13.33 times 10^(-7))/(0.08)` `""=1.67 times 10^(-5)T` For currents in the same direction `B_(p)=2B=3.34 times 10^(-5)T` For currents in the same OPPOSITE direction `B_(p)^(')=` zero. 
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