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Two identical circular wires P and Q each of radius R and carrying current 'I' are kept in perpendicular planes such that they have a common centre as shown in fig. Find the magnitude and direction of the net magnetic field at the common centre of the two coils. |
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Answer» Solution :Magnetic field `B_p` due to current carrying coil `P` = Field BQ due to current carrying coil `Q = (mu_0 I)/(2R)`. Their directions are as shown in fig. As the two field are in mutually PERPENDICULAR directions, HENCE net magnetic field at the common centre O is `B = sqrt(B_(P)^(2) + B_(Q)^(2)) = (mu_0 I)/(sqrt(2)R)` The net field SUBTEND an angle `beta` from `vec(BQ)` such that `tan beta = (BP)/(BQ) = 1` `implies beta = 45^@` 
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