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Two identical containers connected by a fine caillary tube contain air at `N.T.P` if one of those containers is immersed in pure water, boiling under noramal pressure then new pressure isA. `76 cm` of `Hg`B. `152 cm` of `Hg`C. `57 cm` of `Hg`D. `87.76 cm` of `Hg` |
Answer» Correct Answer - D `(P_(1)V_(1))/(T_(1)) = `(P_(1)V_(1))/(T_(1)) = P_(1)((V_(1))/(T_(1)) + (V_(1))/(T_(1)))` |
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