1.

Two identical current carrying coaxial loops, carry current I in an opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C,

Answer»

`oint_(c)vecB*vec(dl)=pm2mu_(0)I`
the VALUE of `oint_(c)vecB*vec(dl)` is independent of sense of C.
there may be a point on C where `vecBandvec(dl)` are perpendicular.
`vecB` vanishes everywhere on C.

Solution :Current in both LOOPS are OPPOSITE to each other, so according to Ampere.s circuital law,
`ointvecB*vec(dl)=mu_(0)sumI`
= `mu_(0)(I-I)=0`
As the MAGNETIC field inside the loop is perpendicular to the direction of plane of loop,
so, `ointBdl=0or|vecB*vec(dl)|cos90^(@)=0`


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