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Two identical magnetic dipoles of magnetic moments 1.0 Am^(2) each placed at separation of 2 m with their axes perpendicualrto each otherfield at a pointmidway between the dipoles is |
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Answer» `5xx10^(-7) T` `therefore B_(1)=(mu_(0))/(4pi)(2M)/(d^(3))`  with respect to `2^(nd)` p lies in broad side on position `therefore B_(2)=(mu_(0))/(4pi)` `B_(1)=10^(-7)xx(2xx1)/(1)=2xx10^(-7)TB_(2)=(B_(1))/(2)=10^(-7)T` As `B_(1)` and `B_(2)` are mutually perpendicular hencetheresultant magnet field `B_(R )=sqrt(B_(1)^(2)+B_(2)^(2))` `sqrt((2xx10^(7))^(2)+(10^(-7))^(2)=sqrt(5)xx10^(-7)T` |
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