Two identical particles `B` and `C` each of mass `50 g` are connected by a light rod of length `30 CM`. Another particle `A` of same mass moving With a speed `u = 60 CM//s` strikes `B`, in a direction perpendicular to `AB`, and sticks to it. The whole process takes place on a smooth horizontal plane. Find the angular velocity `omega` of the system about its centre of mass, immediately after the impact.

Two identical particles `B` and `C` each of mass `50 g` are connected

1.	Two identical particles `B` and `C` each of mass `50 g` are connected by a light rod of length `30 CM`. Another particle `A` of same mass moving With a speed `u = 60 CM//s` strikes `B`, in a direction perpendicular to `AB`, and sticks to it. The whole process takes place on a smooth horizontal plane. Find the angular velocity `omega` of the system about its centre of mass, immediately after the impact.
Answer» Clearly, the centreof mass of the system `(A+B+C)` is at a distance of `10 cm` from along the rod Initial angualr momentum `L_(i)=m_(A) v_(A)r_(A)` `=50xx10^(-3)xx60xx10^(-2)xx10xx10^(-2)` `=3xx10^(-3)` S.I. unit Moment of inertia about new centre of mass `I=(2xx50xx10^(-3))x(10xx10^(-2))^(2)+(50+10^(-3))xx(20xx10^(-2))^(2)` `=3xx10^(-3)` S.I. unit From `L_(i)=L_(f)impliesL_(i)=I.omega` `implies omega=L/i=1rad//s`

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