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Two identical particles move towards each other with velocity 2v and v, respectively. The velocity of the centre of mass is: |
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Answer» v From `vecv_(cm) = (m_1vecV_1 + m_2vecV_2)/(m_1 + m_2) , ""vecV_(cm) = (m xx 2V - mv)/(m + m) = v/2` [The direction of motion of the first particle is taken as positive.]So the velocity of the centre of mass of the system is v/2 in the direction of motion of the particle having LARGER SPEED.
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