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Two identical positive charges are fixed on the y-axis, at equal distances from the origin O. A particle with a negative charge starts on the negative x-axis at a large distance from O, moves along the x-axis, passed through O and moves far away from O. Ita acceleration a is taken as positive along its direction of motion. The particle accleration a is plotter against its x-co-ordinate. Which of the following best represents the plot? |
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Answer» Solution :When the particle is to the left of the ORIGIN O, the net force F on it is towards O and hence, cause acceleration a `F= 2F_(0) cos theta` `=2k (qQ)/((x^(2) + 1^(2))).(x)/(sqrt(x^(2) + 1^(2)))` `=2kQ q(x)/((x^(2) + 1^(2))^(3//2))` F is zero for large values of x and also for x=0. Thus, it must increase to a maximum and fall to zero at O. The acceleration a=F/m, must have the same nature. To the right of O, the net force is to the left while MOTION is to the right. Thus, the direction of a is OPPOSITE to the particle.s direction of motion and is taken as negative. The VARIATION of a with x will follow the same pattern. Hence, 2nd graph REPRESENTS the pattern. 
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