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Two identical resistors of 20 Ω each are connected in parallel. This combination, in turn,is connected to a 10 Ω resistor. The equivalent resistance of the combination will be:

Answer» <p>the formula for parallel connection is</p><p>(1/R1)+(1/R2)=1/Reqhere R1 = 20 OhmsR2=20ohmsso, 1/Req=(1/20)+(1/20) =2/20 =1/10so, Req=10 ohms.this is you are interested is in series with a 10 ohm resistor.so Rtot=10+10=20 ohms</p>


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