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Two identical sources of light are separated through a distance d = (lambda)/(8), where lambda is the wavelength of the waves emitted by either source. The phase difference of the sources is (pi)/(4).Intensitydistribution in the radiation field as a function of theta is : |
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Answer» `4 I_(0) cos^(2)(pi)/(4)` The phase DIFFERENCE between the sources `Delta phi= (pi)/(4)` Also ` x = d sin theta` `therefore phi = (2pi)/(lambda).x = (2pi)/(lambda) .(lambda)/(8) sin theta = (pi)/(4) sin theta` `therefore` Total phase difference, `phi= phi. + Deltaphi. = (pi)/(4) sin theta + (pi)/(4)` or `phi = (pi)/(4)(sin theta + 1)` `therefore` Required INTENSITY is `I = 4I_(0) cos^(2)(phi)/(2)` or `I = 4I_(0)cos^(2)[(pi)/(8)(sin theta + 1)]` |
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