1.

Two identical springs are connected to mass m as shown (k = spring constant). If the period of the configuration (i) is 2 s, the period of the configuration (ii) is

Answer»

`SQRT(2s)`
1s
`1/sqrt(2) s`
`2sqrt(2)s`

Solution :in figure, (i) the two SPRINGS are connected in SERIES.
Therefore, their effective spring constant is,
`k_(s) =((K)(k))/(k+k) = k/2`

`therefore` Time period of oscillation, `T_(s) = 2pi sqrt(m/k_(s))`........(i)
In figure, (ii) the two springs are connected in parallel. Therefore, their effective spring constant is
`k_(p) = k + k = 2k`
`therefore` time period of oscillation, `T_(P) = 2pi sqrt(m/k_(p))`...........(ii)

Divide (i) by (ii), we get
`T_(s)/T_(p) = sqrt(k_(p)/k_(s)) = sqrt((2k)/(k//2)) =2`
or `T_(p) = T_(s)/2 =(2s)/2 = 1s`


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