InterviewSolution
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InterviewSolution
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Two identical thin rings each of radius R are coaxially placed at a distance R. If the rings have a uniform mass distribution and each has masses `2m` and `4m` respectively, then the work done in moving a mass `m` from centre of one ring to that of the other isA. zeroB. `(sqrt(2)Gm^(2))/(R)(1-sqrt(2))`C. `(Gm^(2))/(sqrt(2)R)(sqrt(2)-1)`D. `(Gm^(2))/(sqrt(2)R)` |
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Answer» Correct Answer - B Work done, `W=U_(2)-U_(1)=mv_(2)-mv_(1)` `=m[{-(Gm_(2))/(R)-(Gm_(1))/(sqrt(2)R)}-{-(Gm_(1))/(R)-(Gm_(2))/(sqrt(2)R)}]` `=(Gm(m_(1)-m_(2)))/(sqrt(2)R)(sqrt(2)-1)=(sqrt(2)Gm^(2))/(R)(1-sqrt(2))`. |
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