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Two inclined frictionless tracks, one gradual and the other steep meet at `a` from where two stones are allowed to slide down from rest, one on each track as shown in Figure. Which of the following statement is correct ? .A. Both the stones the bottom at the same time but not with the same speedB. Both the stones reach the bottom with the same speed and stone i reaches the botom earlier than stone IIC. Both the stones reach the bottom with the same speed and stone II reaches the botom earlier than stone ID. Both the stones reach the bottom different times and with different speeds |
Answer» (c ) As the given tracks are frictionless hence, mechaical energy will be conserved. As both the tacks having common height, h From conservation of mechanical energy `(1)/(2)mv^(2)=mgh` (for both tracks I and II) Hence, speed is same for both stone. For stone I, `a_(1)`=acceleration along inclined planed `=g sin theta_(1)` Similarly, for stone II `a_(2)=g sin theta_(2) as theta_(2) gt theta_(1) hence, a_(2) gt a_(1)`, And both length for track II is also less hence, stone II reaches earlier than stone I. |
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