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Two inductors of inductance L_(1) and L_(2) are put in (a) series and (b) parallel with a large separation. Given L_(1)=6H and L_(2)=4H. Calculate the equivalent inductance. |
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Answer» <P> Solution :a. EQ. inductance `L_(s)=L_(1)+L_(2)=10H`b. Eq. inductance `L_(P)=(L_(1)L_(2))/(L_(1)+L_(2))=(6xx4)/(10)=2.4H` |
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