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Two infinite planes each with uniform surfao charge density +sigma C/m^(2) are kept in such a wa m that the angle between them is 30°. Th electric field in the region shown between then is given by: |
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Answer» `sigma/(2epsilon_(0))[(1+sqrt(3)/2)haty - 1/2hatx]` `vecE_(1) = sigma/(2epsilon_(0))(hatj)` `vecE_(2) = sigma/(2epsilon_(0)) SIN60^(@) (-hatj) + sigma/(2epsilon_(0))cos60^(@)(-hati)` `=sigma/(2epsilon_(0)) xx sqrt(3)/2hatj -sigma/(2epsilon_(0)) xx 1/2hati` `THEREFORE` Resultant ELECTRIC FIELD, `VECE =vecE_(1) + vecE_(2)` `=sigma/(2epsilon_(0))hatj - sigma/(2epsilon_(0)) xx sqrt(3)/2hatj - sigma/(2epsilon_(0)) xx 1/2hati` `=sigma/(2epsilon_(0))[(1-sqrt(3)/2)haty - 1/2hatx]` |
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