1.

Two infinite planes each with uniform surfao charge density +sigma C/m^(2) are kept in such a wa m that the angle between them is 30°. Th electric field in the region shown between then is given by:

Answer»

`sigma/(2epsilon_(0))[(1+sqrt(3)/2)haty - 1/2hatx]`
`sigma/(2epsilon_(0))[(1-sqrt(3)/2)haty -1/2hatx]`
`sigma/(2epsilon_(0))[(1-sqrt(3)/2]haty + 1/2hatx]`
`sigma/(2epsilon_(0))[(1+sqrt(3)/2)haty + 1/2hatx]`

Solution :
`vecE_(1) = sigma/(2epsilon_(0))(hatj)`
`vecE_(2) = sigma/(2epsilon_(0)) SIN60^(@) (-hatj) + sigma/(2epsilon_(0))cos60^(@)(-hati)`
`=sigma/(2epsilon_(0)) xx sqrt(3)/2hatj -sigma/(2epsilon_(0)) xx 1/2hati`
`THEREFORE` Resultant ELECTRIC FIELD,
`VECE =vecE_(1) + vecE_(2)`
`=sigma/(2epsilon_(0))hatj - sigma/(2epsilon_(0)) xx sqrt(3)/2hatj - sigma/(2epsilon_(0)) xx 1/2hati`
`=sigma/(2epsilon_(0))[(1-sqrt(3)/2)haty - 1/2hatx]`


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