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Two large metalplates of area 6.0 m^(2)face each other . The plates are 3 cm apart and carry equal and opposite charges on their inner surfaces. If electric field at a point between the plates is5 xx 10 ^(4)NC ^(-1), then calculate the magnitude of charge on each plates. |
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Answer» SOLUTION :Let MAGNITUDE of charge on the inner surface of each plate be Q . It is given that A = `6.0 m^(2)and E = 5 XX 10^(4)C ^(-1) ` At point P between the two PLATES , electric field due to both plates is equal and directed in same direction ,i.e. ` oversetto (E_1) =oversetto (E_2)=(sigma)/( 2 in _0) "" ` [From plate 1 TOWARDS plates 2 ] ` therefore ` Net electric field at point P ` "" E=E_1 +E_2 =(sigma )/( in_0)= (Q)/( in_0A ) ` `rArr ""Q= in _0 AE = 8.85 xx 10 ^(-12)xx 6.0 xx 5 xx 10 ^(4) ` ` "" =2.655 xx10 ^(-6) C or 2.66 muC ` ` (##U_LIK_SP_PHY_XII_C01_E10_023_S01.png" width="80%"> |
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