1.

Two lenses (1) and (2) with R_(1) = R_(2) = 0.20 m each are made from glasses with mu_(1) = 1.2 and mu_(2) = 1.6 respectively. The two lenses with a separation of 0.345 m are submerged in a liquid with mu_(1) = 1.4. The focal lenghts of (1) and (2) are found. An object is placed at a distance of 1.3m from lens 1. The focal lenght of 1 is :

Answer»

0.7 cm
70 cm
`- 70 cm`
`- 0.7 cm`

Solution :(c ) `(1)/(f_(1)) = (.^(1)mu_(g)-1) ((1)/(R_(1)) - (1)/(R_(2)))`
`R_(1) = R = 0.2, R_(2) = - R = - 0.2 m`
`mu_(g) = 1.2, mu_(l) = 1.4`
`THEREFORE f_(1) = - 70 cm`.


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