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Two lenses (1) and (2) with R_(1) = R_(2) = 0.20 m each are made from glasses with mu_(1) = 1.2 and mu_(2) = 1.6 respectively. The two lenses with a separation of 0.345 m are submerged in a liquid with mu_(1) = 1.4. The focal lenghts of (1) and (2) are found. An object is placed at a distance of 1.3m from lens 1. The location of the image while system remains inside the liquid is : |
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Answer» 6.52 m `f_(1) = - 70 cm` = - 70 m `(1)/(v) - (1)/(u) = (1)/(f_(1))` u = - 0.455 m for lens 2 : u = 0.345 - 0.45 = - 0.8 m `(1)/(v) - (1)/(u) = (1)/(f_(2)) v = 5.6` |
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