Saved Bookmarks
| 1. |
Two light beams of intensities I and 4I are used to make interference pattern on a screen. Two points P and Q are marked on the screen where resultant intensities are I_P and I_Q respectively. Phase difference between the waves at point P is pi//2 and the same at Q is pi. Calculate (I_P - I_Q)//I. {:(0,1,2,3,4,5,6,7,8,9):} |
|
Answer» `I = I_1 + I_2 + 2sqrt(I_1I_2) cos DELTA` We can use the above relation to write the FOLLOWING : `I_P = I + 4I + 2sqrt(I xx 4I) cos pi/2 = 5I` `I_Q = I + 4I + 2sqrt(I xx 4I) cos pi = 5I - 4I = I` `implies I_P -I_Q = 5I - I` `implies (I_P - I_Q)/(I) = 4` |
|