Two light waves having the same wavelength lambda in vocume are in phase initially. Then the first ray travels a path of length L_(1) through a medium of refractive index mu_(1). The second ray travels a path of length L_(2) through a medium of refractive index mu_(2). The two waves are then combined to observe interference effects. The phase difference between the two when they interfere, is

Two light waves having the same wavelength lambda in vocume are in pha

1.	Two light waves having the same wavelength lambda in vocume are in phase initially. Then the first ray travels a path of length L_(1) through a medium of refractive index mu_(1). The second ray travels a path of length L_(2) through a medium of refractive index mu_(2). The two waves are then combined to observe interference effects. The phase difference between the two when they interfere, is
Answer» `(2pi)/(lambda)(L_(1) - L_(2))` `(2pi)/(lambda)(mu_(1)L_(1) - mu_(2)L_(2))` `(2pi)/(lambda)(mu_(2)L_(1) - mu_(1)L_(2))` `(2pi)/(lambda)[(Li)/(mu_(1)) - (L_(2))/(mu_(2))]` ANSWER :C

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