1.

Two like poles of strength m_(1) and m_(2)are fardistance apart the energy required to bring them r_(0)distanceapart is

Answer»

`(mu_(0))/(4PI)(m_(1)m_(2))/(r_(0))`
`(mu_(0))/(8pi)(m_(1)m_(2))/(r_(0))`
0
`(mu_(0))/(4pi)(m_(1)m_(2))/(r_(0))`

SOLUTION :`W=triangle U =U_(2)-U_(1)`
`=(mu_(0)m_(1)m_(2))/(4pir_(0))-0=(mu_(0)m_(1)m_(2))/(4pir_(0))`


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