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Two like poles of strength49 xx 10^(-3)A-m and 9 xx 10^(-3)A -m are separated by a distance of 10 cm . Find the distance of the neutral point from the stronger pole wherethe magnetic induction due to the two poles will be zero . |
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Answer» Solution :Let the distance of the netural point from the WEAKER pole `m_1 ` of the magnetic be x then , ` x = (d)/(sqrt((m_2)/(m_1)) + 1) = ( 10)/(sqrt((49 xx 10^(-3))/(9xx 10^(-3)) + 1) = (10)/((7)/(3) +1) = 3 cm` Then the distance of the neutral point from stronger pole = 10CM - 3cm = 7 cm |
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