Two linear SHM of equal amplitudes `A` and frequencies `omega` and `2omega` are impressed on a particle along `x` and `y - axes` respectively. If the initial phase difference between them is `pi//2`. Find the resultant path followed by the particle.

Two linear SHM of equal amplitudes `A` and frequencies `omega` and `2o

1.	Two linear SHM of equal amplitudes `A` and frequencies `omega` and `2omega` are impressed on a particle along `x` and `y - axes` respectively. If the initial phase difference between them is `pi//2`. Find the resultant path followed by the particle.
Answer» Correct Answer - A::B `x = Asin omega t` …(i) `y = Asin(2omega t + pi//2)` `= Acos 2 omega t` `= A(1 - 2 sin ^(2)omega t)` From Eq. (i), `sin omega t = (x)/(A)` `:. Y = A (1 - (2x^(2))/(A))`.

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Two linear SHM of equal amplitudes `A` and frequencies `omega` and `2omega` are impressed on a particle along `x` and `y - axes` respectively. If the initial phase difference between them is `pi//2`. Find the resultant path followed by the particle.

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