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Two liquids A and B have density 1.5 g/cm³ and 0.9 g/cm³ respectively. In which case the wooden piece of density 0.68 g/cm³ will have more portion inside the liquid while floating and why? |
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Answer» Answer: According to Archimedes' principle. Mass of VOLUME displaced is by OBJECT is buoyancy force. Let the volume of wood is V. then the volume submerged in liquid is V/4 let the DENSITY of wood be ρ. let the density of liquid be ρ
=0.8cm −3 . weight of wood ρVg. buoyancy force = 4 ρ l
V
g now weight of BLOCK is equal to buoyancy force. ρVg= 4 ρ l
V
g So ρ= 4 0.8
=.2gcm −3
then the volume submerged in oil is 60% of is 3V/5 weight of wood ρVg buoyancy force = 5 ρ oil
3V
g now weight of block is equal to buoyancy force. ρVg= 5 ρ oil
3V
g So ρ oil
= 3 ρ×5
= 3 0.2×5
=0.33gcm −3 |
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