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Two liquids are at `40^@ C` and `30^@ C`. When they are mixed in equal masses, the temperature of the mixture is `36^@ C`. Ratio of their specific heats isA. `3 : 2`B. `2 : 3`C. `4 : 3`D. `3 : 4` |
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Answer» Correct Answer - A Heat lost by `1^(st)` liquid = Heat gaind by `2^(nd)` liquid. `mS_(1)(40^@ -36^@) = mS_(2)(36^@ -30^@)`. |
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