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Two liquids X and Y form an ideal solution. At 300 K, vapour pressure of the solution containing 1 molof X and 3 mol of Y is 550 mm Hg. At the same temperature if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mm Hg) of X and Y in their pure states will be respectively |
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Answer» 200 and 300 `P_("total")=x_(X)xxp_(X)^(@)+x_(Y)xxp_(Y)^(@)` i.e., `550=0.25p_(X)^(@)+0.75p_(Y)^(@)` `"or"2200=p_(X)^(@)+3p_(Y)^(@)"...(i)"` After adding 1 mol of Y, `x_(X)=(1)/(5)=0.20, x_(Y)=0.80` `THEREFORE""560=0.20p_(X)^(@)+0.80p_(Y)^(@)` `"or"2800 = p_(X)^(@)+4p_(Y)^(@)"...(ii)"` Solving the two EQUATIONS, we get `p_(Y)^(@)=600mm, p_(X)^(@)=400mm` |
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