1.

Two long, parallel wires are separated by a distance of `0.400m` (as shown in Fig.) The current `I_1 and I_2` have the direction shown. (a) Calculate the magnitude of the force exerted by each wire on a 1.20m length of the other. Is the force attractive or repulsive ? (b) Each current is doubled, so that `I_1` becomes 10.0A and `I_2` becomes 4.00A. Now, what is the magnitude of the force that each wire exerts on a 1.20m length of the other?

Answer» (a) `F=(mu_0I_1I_2L)/(2pir)`
`=(mu_0(5.00A)(2.00A)(1.20m))/(2pi(0.400m))=6.00xx10^-6N`
The force is repulsive since the currents are in opposite
directions.
(d) Doubling the current make the force increase by a factor of
4 to
`F=2.40xx10^-5N`


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