Saved Bookmarks
| 1. |
Two magnetic poles of strengths 40Am and 10 Am areseparated by a distance of 20 cm in air. Find the force between them. If the distance is reduced to 10 cm, find the force. |
|
Answer» SOLUTION :i) Pole strength of magnetic POLES , `m_1 = 40 Am and m_2= 10 Am` Distance between the poles , ` d=20 cm = 0.2 m` Force between the magnetic poles ,` (mu_0)/(4pi)(m_1m_2)/(d^(2))` `= (4 pi XX 10^(-7))/(4pi ) xx (40 xx 10)/((0.2)^(2)) = 10^(-3) N` ii) Distance between the poles , `d^(1) = 10 cm = 0.1 m` Forece between the magnetic poles . `F^(1) = (mu_0)/(4pi)(m_1 m_2)/((d^1)^(2))` `= ( 4pi xx 10^(-7))/(4 pi ) xx (40 xx 10)/( (0.1)^(2)) = 4 xx 10^(-3)N`. |
|