InterviewSolution
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InterviewSolution
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Two masses `m_(1) =10 Kg` and `m_(2)=5kg` are connected by an ideal string as shown in the figure. The coefficient of friction between `m_(1)` and the surface is `mu=0.2` Assuming that the system is released from rest calculate the velocity of blocks when `m_(2) has descended by `4m`. `(g=10 m//s^(2))` . |
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Answer» Correct Answer - D `v_(m_1) =v_(m_(2))` `d_(m_1) =h_(m_2) =4m` Using the equation, `E_(i)-E_(f) =` Work done against friction `0-[(1)/(2) xx (10 + 5) (v^(2))-5 xx 10 xx 4]` `=0.2 xx 10 xx 10 xx 4` Solving we get, `v=4m//s` |
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