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Two media each of refractive index 1.5 with plane parallel boundaries are separated by 100 cm. A convex lens of focal length 60 cm is placed midway between them with its principal axis normal to the boundaries. A luminous point object O is placed in one medium on the lens at a distance 125 cm from it. Find the position of its image formed as a result of refraction through the system. |
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Answer» `(n_(2))/(v)-(n_(1))/(u)=(n_(2)-n_(1))/(R), (1)/(v)-(1.5)/((-75))=(1-1.5)/(infty)=0` `(1)/(v)=-(1.5)/(75)v=-50 cm` `u'=-50-50=-100 cm` Object for second refraction. `(1)/(v)-(1)/(u)=(1)/(F)` `(1)/(v)-(1)/(100)=(1)/(60)(1)/(v)=(1)/(60)-(1)/(100)` `v=6xx25=150 cm` `v=150 cm` `|||^(rd)` Refraction `u=150-50=100` `(n_(2))/(v)-(n_(1))/(u)=(n_(2)-n_(1))/(R),(1.5)/(v)-(1)/(100)=0rArr(1.5)/(v) =(1)/(100)` `v=150 cm` from LAST surface `v=150 cm` so from lens `=50+150=200 cm` 
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