1.

Two mercury drops (each of radius 'r') merge to form bigger drop. The surface energy of the bigger drop, if T is the surface tension is :

Answer»

`4pir^(2)T`
`2pir^(2)T`
`2^(8//3)pir^(2)T`
`2^(5//3)pir^(2)T`

SOLUTION :`2. 4/3pir^(3)=4/3piR^(3)`
`R=2^(1//3)r`
`S.E.=T4piR^(2)`
`=T4pi2^(2//3)r^(2)=T2^(5//3)pir^(2)`
CORRECT choice : (d).


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